Question 503166
find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/5(x+6)^2+1 
the vertex is= 
the line of symmetery is= 
what is the man/min of f(x)= 
is the value f(-6)=1, a min or max? 
then graph that represents.
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This is an equation of a parabola of the standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Because lead coefficient is positive, parabola opens upwards, that is, function has a minimum.
..
For given equation:
Vertex:(-6, 1)
Line of symmetry: x=-6
Minimum: 1
f(-6)=1 is a minimum
see graph below:
{{{ graph( 300, 300, -10,5, -10, 10, .2(x+6)^2+1) }}}