Question 502981

Let x be the first integer. So x+1 is the next consecutive integer and x+2 is the next consecutive integer after that.


Now add them up and set this sum equal to 87 and solve for x:


{{{x+(x+1)+(x+2)=87}}}

 
{{{x+x+1+x+2=87}}} 


{{{3x+3=87}}} 


{{{3x=87-3}}} 


{{{3x=84}}} 


{{{x=84/3}}} 


{{{x=28}}} 


So {{{x+1=28+1=29}}} and {{{x+2=28+2=30}}}


This means that the three consecutive integers are 28, 29, and 30