Question 502971
You have 3 unknowns, but since the second and third  equations are the same information (equation 3 is just equation 2 multiplied by 2) you will not have a unique solution so the system will be dependent.

3x - 4y +z = 4
x  + 2y + z = 4
_______________  Subtracting equation 1 from equation 2

2x - 6y = 0, so x = 3y

Substituting this into equation 3

18y - 8y + 2z = 8

10y + 2z = 8, so y = 0.8 - 0.2z, and x = 3y = 2.4 - 0.6z

Substitute the x and y in terms of z into any of the equations will result in an identity equation

(2.4 - 0.6z) + 2(0.8 - 0.2z) + z = 4 (substituted into equation 1)

(2.4 - 0.6z) + (1.6 - 0.4z) + z = 4

4 = 4, true for all values of z

So this is a dependent system

x = 2.4 - 0.6z
y = 0.8 - 0.2z
for any chosen value of z