Question 502953
F = Father
J = John
A = Alice

Now J = 2A, and F = 5J = 5(2A) = 10A

In two years (F + 2) + (J + 2) + (A + 2) = 60, so F + J + A = 54

Substitute all in terms of A

10A + 2A + A = 54, 13A = 54, so A = 54/13 (check your numbers, they usually make these come out in even years)

F = 41.54
J = 8.31
A = 4.15