Question 502886
I'll do the first one to get you started. 


1)


{{{(1/7)(2x-5)=(3/8)x-5/7}}} Start with the given equation.


{{{(1/7)(2x)+(1/7)(-5)=(3/8)x-5/7}}} Distribute.


{{{(2x)/7-5/7=(3/8)x-5/7}}} Multiply.


{{{8(2x)-8(5)=7(3x)-8(5)}}} Now multiply EVERY term by the LCD 56 to clear out the fractions.


{{{16x-40=21x-40}}} Multiply.


{{{16x=21x-40+40}}} Add {{{40}}} to both sides.


{{{16x-21x=-40+40}}} Subtract {{{21x}}} from both sides.


{{{-5x=-40+40}}} Combine like terms on the left side.


{{{-5x=0}}} Combine like terms on the right side.


{{{x=(0)/(-5)}}} Divide both sides by {{{-5}}} to isolate {{{x}}}.


{{{x=0}}} Reduce.


So the solution is {{{x=0}}}