Question 502373
To express the above in the form of a+bi , multiply and divide the expression by the conjugate of the denominator (9-6i).
(-7+6i)/(9+6i)
=((-7+6i) * (9-6i))/(9+6i)(9-6i)
= (-63+54i + 42i -36i^2)/81 -36i^2
= (-63 +96i+ 36)/81+36  (since i^2 = -1)
= (-27 + 96i)/117 
= (-9 + 32i)/39  (divinding by 3)
= -9/39 + 32i/39
= -3/13 + 32i/39

This in the form of a+bi where a = -3/13 and b = 32/39