Question 502162
{{{ 2x^2 - 7x + 6 = 0 }}}
Use the quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{ a = 2 }}}
{{{ b = -7 }}}
{{{ c = 6 }}}
{{{x = (-(-7) +- sqrt( (-7)^2-4*2*6 ))/(2*2) }}} 
{{{x = ( 7 +- sqrt( 49 - 48 )) / 4 }}} 
{{{ x = ( 7 + 1)/4 }}}
{{{ x = 2 }}}
and, also
{{{ x = ( 7 - 1 ) / 4 }}}
{{{ x = 3/2 }}}
The roots are 2 and 3/2
Here's a plot:
{{{ graph( 400, 400, -2, 4, -2, 8, 2x^2 - 7x + 6) }}}