Question 501597
---------percent	----------------			quantity							
Acid I	15	----------------			x	ml						
Acid II	3	----------------	120	-	x	ml						
Mixture	10.00%	----------------	120									
												
15	x	+	3	(	120	-	x	)	=	10	*	120
												
15x+	360	-	3	x	=			1200		
15	x	-	3	x	=	1200	-	360		
12	x			=	840							
/	12											
	x=70	ml			15.00%		Acid I
	50		ml			3.00%		Acid II