Question 500892
Point (x1,y1) = (-8,-7) and point (x2,y2) = (0,-2)

Slope of the line m = y2-y1/x2-x1
                     = (-2 - (-7))/(0-(-8))  = 5/8

Equation of the line is
 y -y1 = m(x-x1)
substiuting the value of m and the value of p9oint x1, y1
y - (-7) = (5/8) * (x - (-8))
y+7 = (5/8)*(x+8)
8y+56 = 5x+40
8y = 5x - 16
=>y = (5/8)*x - 2 is the equation of the line