Question 500758
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Since the radicand must be positive for the function to be defined on the reals, *[tex \Large |x|\ \leq\ 3], hence the domain is the set *[tex \Large \{x\,|\,x\,\in\,\mathbb{R},\,-3\ \leq\ x\ \leq\ 3\}] or in interval notation *[tex \Large \left[-3\,\leq\,x\,\leq\,3\right]]


The largest value the function can assume is when the independent variable is equal to zero, and *[tex \Large h(0)\ =\ \sqrt{9}].   The smallest value is when the independent variable is equal to *[tex \Large \pm 3], and *[tex \Large h(-3)\ =\ h(3)\ =\ 0]


The range is therefore *[tex \Large \left[0\ \leq\ x\ \leq\ 3\right]]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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