Question 50797
Find the x-intercepts of:
{{{y = x^2 - x - 3}}} The x-intercepts are found by setting y = 0.
{{{x^2 - x - 3 = 0}}} Solve using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}} Here: a = 1, b = -1, c = -3
{{{x = (-(-1)+-sqrt((-1)^2 - 4(1)(-3)))/2(1)}}} Simplify.
{{{x = (1+-sqrt(1-(-12)))/2}}}
{{{x = (1+-sqrt(13))/2}}}
{{{x = 2.30277}}}
{{{x = -1.30277}}}