Question 50802
You are given the x-intercept (x = -4) but that is really the point (-4, 0).
Similarly, the y-intercept (y = 4) is really the point (0, 4).
Now with these two points, you can find the slope, m, using {{{m = (y2-y1)/(x2-x1)}}} where:
(-4, 0) = (x1, y1) and (0, 4) = (x2, y2)
{{{m = (4-0)/(0-(-4))}}}
{{{m = 4/4}}}
{{{m = 1}}}

Now you can write, in slope-intercept form {{{y = mx + b}}}:
{{{y = (1)x + b}}} Now substitute the given y-intercept (4) for b.
{{{y = x + 4}}}
Now for the graph:
{{{graph(300,200,-6,5,-5,6,x+4)}}}
As you can see from the graph, the line intercepts the x-axis (x-intercept) at the point (-4, 0) and it intercepts the y-axis (y-intercept) at the point (0, 4).
The slope (rise over run) can be seen, from the graph, to be 1.