Question 500660
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If you double the perimeter of an equilateral triangle, you must, perforce, double the length of each of the sides.  Since the area of an equilateral triangle is given by a numerical constant multiplied times the square of the measure of one of the sides, if you double the measure of a side, you must increase the area by the square of 2, i.e. 4.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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