<PRE><B>Question 500205</B>
Let X be the smallest integer

X + X+2 +X+4 = 2X - 14   (Equation 1)  (Sum of the three integers is 14 less than twice the smallest of these integers)

3X + 6 = 2X -14

3X - 2X = -14-6

X = -20

Answer : Three integers are -20, -18, -16

LHS of Eq 1 : Sum of these three integrers = -54
RHS : 2X - 14 = 2*-20 -14 = -54

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