<PRE><B>Question 500211</B>
	percent	----------------	quantity									
Antifreeze I	10	----------------			5	gal						
Antifreeze II	25	----------------			x	gal						
Mixture	15	----------------	5	+	x	gal						
												
10*5+25x=15(5+x)
50	+	25	x	=	75	+	15	x				
25	x	+	-15	x	=	75	-	-50				
10	x	=	25									
/	10											
x	=	2.5										
		2.5	gal		of	25	% antifreeze II				
</PRE>