<PRE><B>Question 500204</B>
	percent	----------------	quantity									
Alcohol I	30	----------------			9	quarts						
Alcohol II	100	----------------			x	quarts						
Mixture	50	----------------	9	+	x	quarts						
												
30*9+100x=50(9+x)
270	+	100	x	=	450	+	50	x				
100	x	+	-50	x	=	450	-	-270				
50	x	=	180									
/	50											
x	=	3.6										
		3.6	quarts		of	100	%	Alcohol II				
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