Question 500206
	percent	----------------	quantity									
Alcohol I	25	----------------			6	ml						
Alcohol II	5	----------------			x	ml						
Mixture	13	----------------	6	+	x	ml						
												
25	*6+5x	=	13	(	6	+	x	)
150	+	5	x	=	78	+	13	x				
5	x	+	-13	x	=	78	-	-150				
-8	x	=	-72									
/	-8											
x	=	9										
		9	ml		of	5	%	Alcohol II