Question 499737
I'm assuming you want to factor this.





{{{2b^4+14b^3-16b-112}}} Start with the given expression



{{{(2b^4+14b^3)+(-16b-112)}}} Group the terms in two pairs.



{{{2b^3(b+7)-16(b+7)}}} Factor out the GCF {{{2b^3}}} out of the first group. Factor out the GCF {{{-16}}} out of the second group



{{{(2b^3-16)(b+7)}}} Since we have the common term {{{b+7}}}, we can combine like terms



{{{2(b^3-8)(b+7)}}} Factor out the GCF 2 from the first group.



{{{2(b-2)(b^2+2b+4)(b+7)}}} Factor {{{b^3-8}}} using the difference of cubes formula.



So {{{2b^4+14b^3-16b-112}}} factors to {{{2(b-2)(b^2+2b+4)(b+7)}}}



In other words, {{{2b^4+14b^3-16b-112=2(b-2)(b^2+2b+4)(b+7)}}}