Question 499673
{{{12x^2+82x-14 = 0}}} You can solve this by factoring.
{{{(12x-2)(x+7) = 0}}} Apply the "zero product" rule.
{{{12x-2 = 0}}} or {{{x+7 = 0}}} then...
{{{12x = 2}}} so {{{x = 1/6}}} or
{{{x+7 = 0}}} so {{{x = -7}}}
The roots are:
{{{x = 1/6}}} and {{{x = -7}}}