Question 499628
How can I find 3 consecutive integers whose sum is 33?
This is what I have tried.
x+(x+1)+(x+2)=33
I combined the like terms next and got 3x+3=33
I then subtracted three from both sides. -3 -3
I got the answer of 3x=33   ************  33 - 3 = 30, not 33
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after that I divided by 3 on both sides 3x/3 33/3
I got the answer of X=11 
My 3 consecutive integers are 11,12,and 13. 
Is my answer correct?
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Add them and see.
11 + 12 + 13 = 36 <> 33 so no.
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I combined the like terms next and got 3x+3=33
I then subtracted three from both sides. -3 -3
3x = 30
x = 10
--> 10, 11 & 12