Question 499384
Find the center and radius of the circle whose equation is 4x^2+x+4y^2-6y-15=0
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4x^2+x+4y^2-6y-15=0
4x^2+x+4y^2-6y = 15
Complete the squares
x^2+x/4 + y^2- 3y/2 = 15/4
x^2+x/4 + 1/64 + y^2- 3y/2 + 9/16 = 15/4 + 1/64 + 9/16
{{{(x + 1/8)^2 + (y - 3/4)^2 = 277/64}}}
Center at (-1/8,3/4)
{{{radius = sqrt(277)/8}}}