Question 6274
3x^2 + 2x + 1 = 0
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{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 12)]/6
x=[-2 +- sqrt(-8)]/6
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Now the discriminant is less than zero (-8). Therefore there are no real solutions,both will be imaginary.
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square root of -8 = +- 2.8284271247461900976033774484194
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x=[-2 +- i(2.8284271247461900976033774484194)]/6
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Hope this helps,
good luck