Question 499374
1/sqrt(3x+8)
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The domain is affected by the square root function.
We should assume we are limited to the real numbers, so the value of 3x+8 cannot be negative.
Also, since the expression is in a denominator it cannot = 0.
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x = -8/3 would result 0, so that cannot be allowed.
x < -8/3 would result in a negative value, so that cannot be allowed.
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So, the domain of x is all real x > -8/3.
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Done.