Question 499227
write the equation of the line that contains the
: 
x-intercept of 2x+3y=-(x+2y)-12 
x intercept occurs when y = 0 therefore we have
2x + 3(0) = -(x + 2(0)) - 12
2x = -x - 12
2x + x =  -12
3x = -12
x = -4 is the x intercept
:
the y-intercept of 2/3(2x+3y)=6
y intercept occurs when x = 0 therfore
{{{(2/3) (2(0)+3y)}}}= 6
{{{(2/3) (3y)}}}= 6
cancel 3
2y = 6
y = 3 is the y intercept
:
Write the slope intercept form y = mx + b, with these values we have
y = mx + 3
Find m using the x intercept (y=0)
-4m + 3 = 0
-4m = -3
m = {{{(-3)/(-4)}}}
m = {{{3/4}}}
therefore
y = {{{3/4}}}x + 3 is the equation