Question 499172
the diameter and height have increased of a can by 10% how much has the volume increase?
:
radius is also increased by 10%
therefore New vol:Old vol
{{{(pi*(1.1r)^2*1.1h)/(pi*r^2*h)}}} = {{{(pi*1.21*r^2*1.1h)/(pi*r^2*h)}}}
cancel pi, r^2 and h
{{{(1.21*1.1)/1}}} = 1.331, vol increases by 33%