Question 499204
Five consecutive odd integers could be called: a, b, c, d, and e.  That would not be a good choice.  Instead, show them as:
.
x
x+2
x+4
x+6
x+8
.
As long as 'x' is odd, then the next consecutive integer will be +2.  Etc.
.
The sum of the first and fifth;
x + x + 8 = 2x +8
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One less than 3 times the fourth:
3*(x+6) -1
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These two expressions are equal:
2x+8 = 3*(x+6) -1
2x+8 = 3x + 18 -1
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Subtract 8 from both sides
2x = 3x + 18 -1 - 8
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Subtract 3x from both sides
2x -3x = 18 -1 -8
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Collect terms
-x = 9
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Multiply both sides by -1
x = -9
.
Therefore,
x = -9
x+2 = -7
x+4 = -5
x+6 = -3
x+8 = -1
.
They're consecutive odd integers.
.
What is the sum of the first and fifth?
-9 + (-1) = -10
.
What is 3 times the fourth element -1?
3(-3) -1 = -9 -1 = -10
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These all match up with the problem statement and the required answer.
.
Done