Question 498997
Cool problem!
Can't be done!
Sum 1 to 9 is 45.
The sum of all the digits of the 1st two 3 digit numbers + possible carry= 
sum of 3 "answer" digits.
If there is no carry, these 2 "equal" sums add to an even number, not 45.
So there must be a carry.
And the "answer" digits must sum to 23.
Only way is 9 8 6 and to get a carry, 9 would have to be on top too.