Question 498996
<pre> 

Let that same amount of coins of each kind be x.

Then

.01x + .02x + .05x + .10x + .20x + .50x + 1.00x = 282.00

                                          1.88x = 282.00

                                              x = {{{(282.00)/1.88}}}

                                              x = 150

Yes, it is possible to have 150 each of the 7 coins.  
That will be 150×7 or 1050 coins.

Edwin</pre>