<PRE><B>Question 498664</B>
2x^2+19x=-24 i need work for solve each quadratic by factoring
put in the standard form
2x^2 + 19x + 24 = 0
Write, we know both factors will be +
(2x + ___)(x + ___) = 0
determine the factors of 24, 2,12; 3,8; 4;6, If you FOIL, which will agree with
the middle terms 19?
(2x + 3)(x + 8) = 0
2x = -3
x = {{{-3/2}}}
and
x = -8
:
:
2(x-3)^2 = 8 by using square roots
divide both sides by 2, and you have
(x-3)^2 = 4
Find the square root of both sides and you have:
x - 3 = 2
add 3 to both sides
x = 2 + 3
x = 5
:
Check in the original equation
2(5-3)^2 = 8
2(2^2) = 8</PRE>