Question 50603
For a sphere 


Volume: {{{V=  (4/3)*pi*r^3)}}} and 
Surface area:  {{{A=4*pi* r^2}}}


{{{64*pi = 4 *pi* r^2}}}


Divide both sides by {{{4 pi}}}:
{{{ 16 = r^2}}} so r= 4.


Therefore, {{{V=  (4/3)*pi*r^3)}}} 
{{{V=  (4/3)*pi*4^3)}}} 
{{{ V =(256*pi)/3}}}


R^2 at SCC