Question 498536
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If you had 5 different digits, then you would have 5! ways to arrange them and therefore 5! distinct 5 digit numbers.  Since three of your digits are the same, 3! of your 5! 5 digit numbers are identical, so the calculation is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5!}{3!}\ =\ \frac{5\ \times\ 4\ \times\ 3\ \times\ 2}{3\ \times\ 2}]


Do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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