Question 498222
if you have this:

{{{(x-1)=sqrt(5x-9)}}}


{{{(x-1)^2=(sqrt(5x-9))^2}}}


{{{x^2-2x+1=5x-9}}}


{{{x^2-2x+1-5x+9=0}}}


{{{x^2-7x+10=0}}}.......replace {{{-7x}}} with {{{-2x-5x}}}


{{{x^2-2x-5x+10=0}}}


{{{(x^2-2x)-(5x-10)=0}}}


{{{x(x-2)-5(x-2)=0}}}


{{{(x-5)(x-2)=0}}}

solutions:

{{{x-5=0}}}.....->.......{{{x=5}}}

or

{{{x-2=0}}}.....->.......{{{x=2}}}


{{{ graph( 500, 500, -6, 15, -10, 10, x^2-7x+10) }}}