Question 498076
Assume that f(x) = 3/2, that is


*[tex \LARGE \frac{3x-1}{2x+4} = \frac{3}{2}]


Then, *[tex \LARGE 2(3x-1) = 3(2x+4) \Rightarrow -2 = 12], contradiction, so 3/2 cannot be in the range.


Technically, the value of f(x) approaches 3/2 as x gets larger and larger.