Question 497518
Bird I 500 mph
Bird II 1500 mph

In 10 minutes = 1/6 hour bird I travels 500*1/6 = 83.33 miles.

difference between their speeds = 1000 

d= 83.33
speed = 1000 mph

time = d/r
83.33/1000 
0.0833 hours
0.0833*3600= 300 seconds

time to catchup = 300 seconds