<PRE><B>Question 497313</B>
can you please help me solve this polynomial equation (x^3+8) by factoring and using the principle of zero products?
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Solve: x^3+8 = 0
Factor:
(x+2)(x^2-2x+4) = 0
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x = -2 and
Solve x^2-2x+4 = 0
x = [2 +- sqrt(4-4*4)]/2
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x = [2 +- sqrt(-12)]/2
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x = [2 +- 2sqrt(3)i]/2
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x = 1+sqrt(3)i or x = 1-sqrt(3)i
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Cheers,
Stan H.</PRE>