Question 497259
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Step 1:  Determine the slope of the line described by the given equation.  Since the given equation is in slope intercept form, the slope of the line described by that equation is the coefficient on *[tex \Large x].


Step 2:  Determine the slope of the desired line.  The slopes of perpendicular lines are negative reciprocals.  That is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


Hence, calculate the negative reciprocal of the slope value determined in step 1.


Step 3:  Use the point-slope form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope from step 2.


Step 4:  Rearrange your result in to slope-intercept from, namely: *[tex \Large y\ =\ mx\ +\ b]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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