Question 497038
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This is a commutative and associative property problem.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(6z\right)\left(\frac{x}{2}\right)\left(12y\right)\ =\ (6)(z)\left(\frac{1}{2}\right)(x)(12)(y)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (6)(z)\left(\frac{1}{2}\right)(x)(12)(y)\ =\ (6)\left(\frac{1}{2}\right)(12)(x)(y)(z)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (6)\left(\frac{1}{2}\right)(12)(x)(y)(z)\ =\ (6)\left(\frac{1}{2}\right)(12)(xyz)]


Now all you have to do is substitute the value you know for *[tex \Large xyz] and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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