Question 496280
Factor out a and complete the square:


*[tex \LARGE ax^2 + bx + c = 0 \Rightarrow x^2 + \frac{b}{a}x + \frac{c}{a} = 0]


*[tex \LARGE (x + \frac{b}{2a})(x + \frac{b}{2a}) + (\frac{c}{a} - \frac{b^2}{4a^2}) = 0]


*[tex \LARGE (x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{c}{a} = \frac{b^2 - 4ac}{4a^2}]


Take the square root of both sides and solve for x.