Question 50578
<blockquote>"The perimeter of an isosceles triangle is 40, and the base is 10. find the length of one of the equial sides."</blockquote>
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<pre><tt><b>P</b><sub>erimeter</sub>=B<sub>ase</sub>+S<sub>ide</sub>+S<sub>ide</sub>

Thence;
40=B+S+S

We know S and S [two sides] are the same, because the triangle is an isosceles.
The equation thence yields:
40=B+2S

B is 10:
40=10+2S   minus 10 to both sides
30=2S      divide both sides by 2
15=S

each side is 15. 

let's check: 
2(15)+10=40
30+10=40
40=40 :-D it works.</tt></pre>