Question 496178
Hello, 
Let's solve this by substituting:
y=x^2+4
y-4x=1
Plug first equation into the second as:
x^2+4-4x=1
rearrange and subtract 1 to get:
x^2-4x+3=0
Factor:
(x-3)(x-1)=0
Solve for x:
x=3  y=13
x=1  y=5
Make sense?
RJ
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