Question 495508
Three integers, a, b, c
:
the sum of three integers is one hundred twenty-three.
a + b + c = 123
:
The second number is two more than twice the first number.
b = 2a + 2
:
The third number is five less than the product of three and the first number.
c = 3a - 5
:
Replace b and c in the 1st equation, find a
a + (2a+2) + (3a-5) = 123
Combine like terms
6a - 3 = 123
6a = 123 + 3
6a = 126
a = {{{126/6}}}
a = 21
:
I'll let you find b and c, check by finding the sum of all three values