Question 50408
((8x^3)/(x-1))/((7x^2)/((x^3)-1))

[(8x^3)/(x-1)] * ((x^3-1)/(7x^2))

At this point you have to know the following:
x^3-1=(x-1)(x^2+x+1).
If you see this you see the (x-1) factors cancel giving you the following:

(8x^3)*(x^2+x+1)/(7x^2)

=(8/7)x(x^2+x+1)
(8/7)(x^3+x^2+x)

Cheers,
Stan H.








=