Question 495128
Vertex of x^2+3x+2
standard form of an equation for a parabola: y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
..
y=x^2+3x+2
completing the square
y=(x^2+3x+9/4)+2-9/4
y=(x+3/2)^2-1/4
ans:
coordinates of vertex: (-3/2,-1/4)