Question 495128
Vertex of x^2+3x+2
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vertex occurs at x = -b/(2a) = -3/2
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The y-value is (-3/2)^2 + 3(-3/2) + 2 = 9/4-9/2+2 = -1/4
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Vertex = (-3/2, -1/4)
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Cheers,
Stan H.
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