<PRE><B>Question 495141</B>
Two cars travel toward each other at constant velocities. One is going 12 m/s, and the other 18 m/s. They are 3000m apart when we first see them. 
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Their closing rate is (10+18)m/s = 28 m/s
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time = distance/rate
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time = 3000m/28 = 107.17 seconds
The trains will meet in 107.17 sec
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Cheers,
Stan H.
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