Question 494849
"three consecutive odd integers"
x, (x+2), (x+4) 
:
"three times the sum of the first two integers is ten more than the product of the third integer and four."
3(x + (x+2)) = 4(x+4) + 10
3(2x + 2) = 4x + 16 + 10
6x + 6 = 4x + 26
6x - 4x = 26 - 6
2x = 20
x = 20/2
x = 10
:
10, 12, 14, these are not odd but the only integers that satisfy the given statement