Question 494708
if a square have the sides x+4, and a diagonal line of x+8 what is the value of x?
(how would you set that problem up)
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Using pythag c^2 = a^2 + b^2
both a and b = x+4) and c = (x+8) so we have
(x+8)^2 = 2(x+4)^2
FOIL
x^2 + 16x + 64 = 2(x^2 +8x + 16)
x^2 + 16x + 64 = 2x^2 + 16x + 32
Combine like terms on the right
0 = 2x^2 - x^2 + 16x - 16x + 32 - 64
x^2 - 32 = 0
x^2 = 32
x = {{{sqrt(32)}}}
x = {{{4*sqrt(2)}}} is the value of x
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