Question 494455
Find the remaining trig functions of theta if cos theta=-square root of 3 over 2 and terminates in Q II.
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using x in place of theta
cosx=-√3/2
x=&#960;/6 (reference angle in quadrant II where cos<0, sin>0, tan<0)
sinx=1/2
tanx=-1/&#8730;3=-&#8730;3/3
secx=-2/&#8730;3=-2&#8730;3/3
cscx=2
cotx=-&#8730;3