Question 494611
a)solve the following trigonometric equation for 0 degrees x 360 (there are arrows and are underlined pointing to the left hand side one after degrees and another after the x) 
sin(x) - 2 sin^2 (x) = 0 
Factor:
sin(x)[1 - 2sin(x)] = 0
---
sin(x) = 0 or sin(x) = 1/2
---
x = 0, or 180  OR x = 30 or 150 degrees
==============================================

b)prove the following trigonometric identity
sin(x) + sin(x)* cot^2(x) = csc(x)
---
sin(x)[1 + cot^2(x)] = csc(x)
---
sin(x)[csc^2(x)] = csc(x)
---
sin(x)*1/sin^2(x) = csc(x)
---
1/sin(x) = csc(x)
----
csc(x) = csc(x)
=======================
Cheers,
stan H.
==============