Question 494592
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You have a cube of water 15" on each edge.  The volume of a cube is the measure of an edge cubed.  For you:  


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 15^3\ in^3]


The weight of the water is simply the weight of a cubic inch of water multiplied by the total number of cubic inches.


You should round your answer to the nearest pound because, even though the pounds per cubic inch factor was given to three decimal places, the measure of each edge of the cube of water was given to the nearest inch.  Never provide the result of a calculation involving measurement to a greater precision than the least precise given measurement.  Unless, of course, you have a compelling reason to do so such as your professor's instructions for a given problem.


Oh, and by the way just in case you haven't figured it out by now -- you get to do all of your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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